| Established in 1952 | |
Page: 2150 |
The answer is calculated by multiplying the volume of the ball by the density of the material.
Weight = Volume * Density
Volume = (4 * 
* R * R * R)/ 3, or Volume = ( 4 * Pi
* Radius ^ 3 ) / 3
, Pi, a universal constant = 3.1416
4 = 12.566
R=Radius
R=Diameter / 2 = 2 / 2 = 1
R^3 = R * R * R = 1
12.566 x 1 = 12.566
12.566 / 3 = 4.1887 cubic inches (is the volume of a 2 inch ball)
4.1887 times the density of lead, which is 0.409 pounds per cubic inch, gives a weight of 1.713 pounds.
What would a 3 inch diameter lead ball weigh?
The radius of 1.5 inches cubed equals 3.375, times 12.566 ( 4
x ) equals
42.410, divided by three, equals 14.137 cubic inches, times 0.409
( the density of lead ) gives 5.782 pounds.
Weight = Volume * Density
Weight = [(4 * * R * R * R)/ 3 ] * 0.409
Weight = [ ( 4 * 3.1416 * (3/2) * (3/2) * (3/2) /3 ] * 0.409
Weight = 5.782 pounds
Notice that only one inch increase in diameter caused a 4 pound increase in weight. This three inch diameter ball is more than triple the weight of the two inch diameter ball.
|
Material
|
Density ( pounds / cubic inch )
|
| Aluminum | 0.0975 |
| Brass | 0.3048 |
| Cast Iron | 0.26 |
| Copper | 0.321 |
| Lead | 0.409 |
| Magnesium | 0.0628 |
| Steel | 0.283 |
| Titanium | 0.162 |
| Zinc | 0.254 |
| Material | Density ( grams / cm ^3 ) |
| 300 Stainless Steel | 8.02 |
| Aluminum Alloy | 2.73 |
| Brass | 8.47 |
| Copper | 8.91 |
| Gray Iron | 7.2 |
| Lead | 11.35 |
| Magnesium | 1.77 |
| Monel | 8.9 |
| Steel | 7.86 |
| Titanium | 5.0 |
| Water ( liquid ) | 1.00 |
| Zinc | 7.14 |
Copyright © 1999-2006
Micro Surface Engr. Inc. |
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